MPSC Civil Engineering(2021) Booklet Code (D) Q.60 An airplane begins its take-off run at A with zero velocity and a constant acceleration . Knowing that it becomes airborne 30 seconds later at B and that the distance AB is 900m, What is the acceleration and take-off velocity of airplane?

Given :-

Va = 0 (Intial Velocity)                                       a = 0 (Acceleration)        

Xa = 0                                                                Xb = 900 m ( Distance)            

Tb = 30 s ( Time form A to B) 

Calculate acceleration and velocity of airplane?

Solution :- 

a = a₀ = Va

Va= a₀ t + Va

     = a₀ t   =  x

x   =  1/2  a₀ t  +  Xa 

     = 1/2  a₀ t  + 0

     =  1/2  a₀ t 

Xb = 900 m

      = ½ a₀ (30 s)²

         = 2 m/s²

Vb = (2 m/s² ) (30 s)

      = 60 m/s

The acceleration of airplane =  2 m/s²      & The Velocity of airplane =   60 m/s